Espresso: return boolean if view exists

I am trying to check to see if a view is displayed with Espresso. Here is some pseudo code to show what I am trying:

if (!Espresso.onView(withId({
   // then do something
 } else {
   // do nothing, or what have you

But my problem is .check(doesNotExist()) does not return boolean. It is just an assertion. With UiAutomator I was able to just do something like so:

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  •  if (UiAutomator.getbyId(SomeId).exists){

    I found this; check line 46. Still can’t find out how to use it.

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  • 5 Solutions collect form web for “Espresso: return boolean if view exists”

    We need that functionality and I ended up implementing it below:

    if(onView(withText("click OK to Continue")).exists()){ 
    } else { 

    I hope it is useful for you.

    Conditional logic in tests is undesirable. With that in mind, Espresso’s API was designed to guide the test author away from it (by being explicit with test actions and assertions).

    Having said that, you can still achieve the above by implementing your own ViewAction and capturing the isDisplayed check (inside the perform method) into an AtomicBoolean.

    Another less elegant option – catch the exception that gets thrown by failed check:

        try {
            onView(withText("my button")).check(matches(isDisplayed()));
            //view is displayed logic
        } catch (NoMatchingViewException e) {
            //view not displayed logic

    You check with the below code also. If view is displayed it will click else it will pass on.

    onView(withText("OK")).withFailureHandler(new FailureHandler() {
            public void handle(Throwable error, Matcher<View> viewMatcher){

    I think to mimic UIAutomator you can do this:
    (Though, I suggest rethinking your approach to have no conditions.)

    ViewInteraction view = onView(withBlah(...)); // supports .inRoot(...) as well
    if (exists(view)) {
    public static boolean exists(ViewInteraction interaction) {
        try {
            interaction.perform(new ViewAction() {
                @Override public Matcher<View> getConstraints() {
                    return any(View.class);
                @Override public String getDescription() {
                    return "check for existence";
                @Override public void perform(UiController uiController, View view) {
                    // no op, if this is run, then the execution will continue after .perform(...)
            return true;
        } catch (AmbiguousViewMatcherException ex) {
            // if there's any interaction later with the same matcher, that'll fail anyway
            return true; // we found more than one
        } catch (NoMatchingViewException ex) {
            return false;
        } catch (NoMatchingRootException ex) {
            // optional depending on what you think "exists" means
            return false;

    Also exists without branching can be implemented really simple:

    onView(withBlah()).check(exists()); // the opposite of doesNotExist()
    public static ViewAssertion exists() {
        return matches(anything());

    Though most of the time it’s worth checking for matches(isDisplayed()) anyway.

    Based on the answer by Dhiren Mudgil, I ended up writing the following method:

    public static boolean viewIsDisplayed(int viewId)
        final boolean[] isDisplayed = {true};
        onView(withId(viewId)).withFailureHandler(new FailureHandler()
            public void handle(Throwable error, Matcher<View> viewMatcher)
                isDisplayed[0] = false;
        return isDisplayed[0];

    I’m using this to help determine which View in a ViewFlipper is currently displayed.

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